2(a^2+1)=5a

Solution for 2(a^2+1)=5a equation:

Simplifying
2(a2 + 1) = 5a

Reorder the terms:
2(1 + a2) = 5a
(1 * 2 + a2 * 2) = 5a
(2 + 2a2) = 5a

Solving
2 + 2a2 = 5a

Solving for variable 'a'.

Reorder the terms:
2 + -5a + 2a2 = 5a + -5a

Combine like terms: 5a + -5a = 0
2 + -5a + 2a2 = 0

Factor a trinomial.
(1 + -2a)(2 + -1a) = 0

Subproblem 1
Set the factor '(1 + -2a)' equal to zero and attempt to solve:

Simplifying
1 + -2a = 0

Solving
1 + -2a = 0

Move all terms containing a to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2a = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2a = 0 + -1
-2a = 0 + -1

Combine like terms: 0 + -1 = -1
-2a = -1

Divide each side by '-2'.
a = 0.5

Simplifying
a = 0.5
Subproblem 2
Set the factor '(2 + -1a)' equal to zero and attempt to solve:

Simplifying
2 + -1a = 0

Solving
2 + -1a = 0

Move all terms containing a to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1a = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1a = 0 + -2
-1a = 0 + -2

Combine like terms: 0 + -2 = -2
-1a = -2

Divide each side by '-1'.
a = 2

Simplifying
a = 2
Solution
a = {0.5, 2}